Subtract the Product and Sum of Digits of an Integer | Leetcode

Hey, coders welcome to our new series of solving programming questions. So we are back with the Leet Code solution in C++ and Python, so let’s start.

Problem Statement
Given an integer number n, return the difference between the product of its digits and the sum of its digits.

Example 1:

Input: n = 234
Output: 15
Explanation:
Product of digits = 2 * 3 * 4 = 24
Sum of digits = 2 + 3 + 4 = 9
Result = 24 - 9 = 15

Example 2:
Input: n = 4421
Output: 21
Explanation:
Product of digits = 4 * 4 * 2 * 1 = 32
Sum of digits = 4 + 4 + 2 + 1 = 11
Result = 32 - 11 = 21

C++ Solution

class Solution {
public:
    int subtractProductAndSum(int n) {
        int sum = 0;
        int product = 1;
        while(n != 0){
            int digit = n % 10;
            sum += digit;
            product = product * digit;
            n = n / 10;
        }
        int subtract = product - sum;
        return subtract;
    }
};

Python3 Solution

def subtractProductAndSum(n):
    sums = 0
    product = 1

    while(n != 0):
        digit = n % 10
        sums += digit
        product = product * digit
        n = n // 10
    return (product - sums)
print(subtractProductAndSum(234))

So this was the simplest solution for this problem you can also try different approaches to solve this problem in an efficient way.

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